A dielectric slab of thickness 1.0 cm and dielectric constant 5 is placed between the plates of a parallel plate capacitor of plates area
and separation 2.0 cm.
Column I | Column II | ||
A. | Capacity with air in between the plates | I. | 2.95 F |
B. | Capacity with dielectric slab in between the plates | II. | 8.85 F |
C. | Capacity with conducting slab in between the plates | III. | 7.375 F |
D. | Increase in capacity on introduction of dielectric | IV. | 4.425 F |
Choose the correct answer from the options given below
Text Solution
Verified by ExpertsB
Given,

Capacity with air in between the plates 

Capacity with dielectric slab in between the plates


Capacity with conducting slab in between the plates


Increase in capacitance on introduction of dielectric



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